Ti̍t-chiap chèng-bêng

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()數學 (sò͘-ha̍k) (kap) ()chek直接 (ti̍t-chiap)證明 (chèng-bêng) (direct proof) ()1 (chióng)直接組合 (cho͘-ha̍p)公設 (kong-siat)定義 (tēng-gī)事實 (sū-si̍t)小定理 (sió-tēng-lí) (lemma),定理 (tēng-lí) (lâi)說明 (soeh-bêng)1 (ê)陳述 (tîn-su̍t)正實的 (chiaⁿ-si̍t--ê) (ia̍h)假的 (ké--ê) (ê)過程 (koè-têng)過程呢 (Kòe-têng--nih) (thaû)1 (pō͘) (kaù) (kah) (siōng) (boé)結論 (kiat-lūn) (lóng)著愛 (tio̍h-ài) (ēng)演繹 (ián-e̍k) (deduction) 的邏chek來進行 (chìn-hêng)用著 (Ēng--tio̍h)的邏chek差不多 (chha-put-to)攏是包含 (pau-hâm)全部 (choân-pō͘)的 ...(for all) 抑存在 (chûn-chāi) ...(there exists) 的一階 (it-kai)邏chek。上 (chia̍p)用著的證明規則 (kui-chek)MP (modus ponens), ()2捷用的 (ēng--ê)MT (modus tollens); 邏chek轉換 (choán-oāⁿ) (transposition) (ham)MTP (disjunctive syllogism) () (chin)好用 (hó-ēng)

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(Chit) ()直接證明來證明雙數 (siang-sò͘) (ke)雙數 (iáu)相數 (siang-sò͘)

考慮 (Khó-lū)2个雙數 解析失敗 (Chīn-liōng iōng MathML (chhì-giām-sèng--ê):從伺服器 "https://wikimedia.org/api/rest_v1/" 收到無效的回應 ("Math extension cannot connect to Restbase.")。): {\displaystyle x}解析失敗 (Chīn-liōng iōng MathML (chhì-giām-sèng--ê):從伺服器 "https://wikimedia.org/api/rest_v1/" 收到無效的回應 ("Math extension cannot connect to Restbase.")。): {\displaystyle y}因為 (In-ūi) (in)攏是相數,會當 (ē-tàng) () (siá) (chò) 解析失敗 (Chīn-liōng iōng MathML (chhì-giām-sèng--ê):從伺服器 "https://wikimedia.org/api/rest_v1/" 收到無效的回應 ("Math extension cannot connect to Restbase.")。): {\displaystyle x=2a}解析失敗 (Chīn-liōng iōng MathML (chhì-giām-sèng--ê):從伺服器 "https://wikimedia.org/api/rest_v1/" 收到無效的回應 ("Math extension cannot connect to Restbase.")。): {\displaystyle y=2b}解析失敗 (Chīn-liōng iōng MathML (chhì-giām-sèng--ê):從伺服器 "https://wikimedia.org/api/rest_v1/" 收到無效的回應 ("Math extension cannot connect to Restbase.")。): {\displaystyle a}解析失敗 (Chīn-liōng iōng MathML (chhì-giām-sèng--ê):從伺服器 "https://wikimedia.org/api/rest_v1/" 收到無效的回應 ("Math extension cannot connect to Restbase.")。): {\displaystyle b} (khah) ()整數 (chéng-sò͘)按呢 (Án-ne)解析失敗 (Chīn-liōng iōng MathML (chhì-giām-sèng--ê):從伺服器 "https://wikimedia.org/api/rest_v1/" 收到無效的回應 ("Math extension cannot connect to Restbase.")。): {\displaystyle x+y = 2a + 2b = 2(a+b)} () () (kóng) 解析失敗 (Chīn-liōng iōng MathML (chhì-giām-sèng--ê):從伺服器 "https://wikimedia.org/api/rest_v1/" 收到無效的回應 ("Math extension cannot connect to Restbase.")。): {\displaystyle x+y} 是2个倍數 (poē-sò͘), 1个雙數。所以 (Só͘-í)2个雙數家做伙 (chò-hoé)定著 (tiāⁿ-tio̍h)嘛是相數。